In the lab, Kira has two solutions that contain alcohol and is mixing them with each other. She uses 200 milliliters less of Solution A that Solution B. Solution A is 10% alcohol and Solution B is 20% alcohol. How many milliliters of Solution B does she use, if the resulting mixture has 340 milliliters of pure alcohol?

Kira use 1200 ml of solution B.

Step-by-step explanation:

Given:

Two solution with percentage of alcohol.

Percentage of alcohol in solution A = =

Percentage of alcohol in solution B = =

Quantity of pure alcohol, in (A+B) mix =  ml

According to the question:

Kira uses milliliters less of Solution A that Solution B.

So,

⇒             ...equation (i)

In terms of total quantity and percentage we can re-write it as,

⇒    ...equation (ii)

Substituting the value of A from equation (i) in equation (ii).

⇒

⇒

⇒  

⇒

⇒  ...adding 20 both sides

⇒

⇒                             ...dividing 0.3 on both sides  

⇒ ml

She uses 1200 milliliters of solution B where the resulting mixture has 340 ml of pure solutions.

i think the amount would be $140.62

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%