What is the exact value of this?

Correct  second quadrant  angle is 3π/4

                            fourth answer  (2√2 + π) / 4

                            third quadrant angle is 5π/4

                            first answer  (-2√2 + π) / 4

Step-by-step explanation:

Your question does not define the quadrant in which the angle is of the

cos⁻¹ (- √2/2).

If it is in the second quadrant then the angle is 3π/4 and if it is in the third quadrant then the angle is 5π/4

1) second quadrant  angle is 3π/4

sin ( cos⁻¹ (- √2/2)) + tan⁻¹ ( sin ( π/2)) = sin ( 3π/4) + tan⁻¹ 1 =

=  √2/2 + π/4 = (2√2 + π) / 4

2) third quadrant angle is 5π/4

sin ( cos⁻¹ (- √2/2)) + tan⁻¹ ( sin ( π/2)) = sin ( 5π/4) + tan⁻¹ 1 =

= - √2/2 + π/4 = (-2√2 + π) / 4

God is with you!!!

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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