Scores of each of the previous calculus tests were normally distributed with a mean of 74 and standard deviation of 3.8. Steve will be taking the test tomorrow. What is the P(z<-1.05)?

-2.2 (-2.2124%)  is the answer as -2.2124^2 = -4.89% is found first below. -2.2124 is part of the derivation equation to find the relation with z.

z<-1.05 therefore = -2.2<-1.05

Step-by-step explanation:

-4.89%

-0.27631578947 x 74= -20.4473684208

P)z<-105) =  100/-20.4473684208 = -4.89060489067 less than the population of 100%

0 =population standard deviation = 3.8 we divide from 1.05

(in normal derivation questions we can multiply before dividing 0 key letter =(z- u)^2 / divide all by N) This is why we divided.

N=the size of the population = 100/D we used 100/D to find the first part.

z=each value from the population  = z<-1.05

u=the population mean = 74 we multiplied second step after first step 3.8 we divide from 1.05

So that 1.05/3.8 = -0.27631578947 x 74 = D

We then Divide into N = 100/D

to find a whole or a percentage.

= -4.89

z = -2.2

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( =