What are the answers to the letters and how did you get that?

Step-by-step explanation:

You need to take advantage of what you have learned about inscribed angles. Each inscribe angle is half the measure of the arc it intercepts. Of course, the sum of all arcs around a circle is 360°.

Putting these facts together, you can quickly conclude that opposite angles of an inscribed quadrilateral are supplementary:

  a = 180 -110 = 70

  b = 180 -102 = 78

The arc (c+81) is opposite the inscribed angle marked 110, so we have ...

  c + 81 = 2(110)

  c = 220 -81 = 139

The arc (c+d) is intercepted by the angle marked b, so we have ...

  139 +d = 2(78)

  d = 156 -139 = 17

The arc (e+81) is intercepted by the inscribed angle marked 102, so ...

  e +81 = 2(102)

  e = 204 -81 = 123

The inscribed angle f intercepts arc c, so is half its measure.

  f = 139/2 = 69.5

19.side- angle- side

20. angle- side- angle

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.