Find four consecutive even integers such that if the sum of the first and third is multiplied by 3, the result is 28 less than five times the fourth

Step-by-step explanation:

We can solve the problem in this way:

- The 1st information that we have is that the four numbers are even and consecutive integer. Let's call these numbers A, B, C and D. This means that:

(since the distance between two even consecutive numbers is 2)

- The 2nd information that is given is that the sum of the first and third multiplied by 3 equals 28 less than 5 times the fourth, so:

(1)

Now we rewrite eq(1) by using:

and

(obtained by combining the 3 first equations)

So we get:

Solving this equation for C,

So the other numbers are:

because 1.2 isnt half of 6 duh

the answer is b.

step-by-step explanation:

by the trigonometric ratio tangent, tangent equals opposite divided by adjacent.

therefore, tan(50) equals ac/3

multiply each side by 3 to get: ac=3tan(50)

the answer is b.