Given the median QR and trapezoid mnpo, what is the value of x?
MN = 17
QR = X+12
OP = 5X-14

The answer for the image is written below.

Given:

Measure of ∠T = (4x + 12)°

Measure of ∠P = 2x°

To find:

The value of x.

Solution:

By the property of isosceles trapezoid:

Adjacent angles corresponding to parallel sides are supplementary.

m∠T + m∠P = 180°

(4x + 12)° + 2x° = 180°

4x° + 12° + 2x° = 180°

Add like terms.

6x° + 12° = 180°

Subtract 12° from both sides.

6x° + 12° - 12° = 180° - 12°

6x° = 168°

Divide by 6 on both sides, we get

x° = 28°

x = 28

The value of x is 28.

b 1: 45 am

step-by-step explanation:

its that because if it was in the pm it would be 1345