Solve the system of linear equations.

6x - 2y = -18

2x - 2y = -2

x = -4

y = -3

Step-by-step explanation:

to solve the system of linear equation we say that let

6x - 2y = -18 equation 1  

2x - 2y = -2 equation 2

from equation 2

2x - 2y = -2 equation 2

2x = -2  + 2y

divide both sides by 2

2x/2 = ( -2 + 2y)/2

x =  ( -2 + 2y)/2 equation 3

substitute for x in equation 1

6x - 2y = -18 equation 1

6[( -2 + 2y)/2]  - 2y = -18

-6 + 6y- 2y = -18

collect the like terms

6y - 2y = -18 + 6

4y = -12

divide both sides by the coefficient of y which is 4

4y/4 = -12/4

y = -3

put y = -3 in   equation 3

x =  ( -2 + 2y)/2 equation 3

x = -2 + 2(-3)/2

x = -2-6/2

x = -8/2

x = -4

therefore the value of x and y in the equation is -4 and -3 respectively.

hope this !

step-by-step explanation:

d = distance between moon and sun, which in this problem is the hypotenuse of a right triangle.  

the distance y is the side opposite to angle x in the right triangle.   use the definition of the sine function from basic trigonometry.

sin(x) = y/d ⇒

d = y/sin(x)

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a