A flat roof 22 feet long and 12 feet wide has an 8 inch depth of water sitting on it. What is the weight of the water on the roof?

see the explanation

Step-by-step explanation:

step 1

Find the volume of the water

we know that

The volume of water on the roof can be found by multiplying the length of the roof  by  the width of the roof  by the depth of the water.

so

where

L is the length

W is the width

H is the deep of the water

Remember that

we have

substitute

step 2

Find the weight of the water

we know that

The density of water is equal to

Multiply the density by the volume to obtain the weight of the water

Convert to kilograms

Remember that

so

That's 4.9 tons of water pushing down on that roof

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

the answer will be