An earthquake of magnitude 3.0 is $10^2$ times stronger than an earthquake of magnitude 1.0. An earthquake of magnitude 8.0 is $10^7$ times stronger than an earthquake of magnitude 1.0. How many times stronger is an earthquake of magnitude 8.0 than an earthquake of magnitude 3.0?

10^5

Step-by-step explanation:

The magnitude of an earthquake refers to the strength or "size" of an earthquake. This is usually determined based on measurements of the seismic waves recorded on a seismogram.

In this example, we learn that a magnitude 3 earthquake is 10^2 times stronger than a magnitude 1 earthquake, and a magnitude 8 earthquake is 10^7 times stronger than a magnitude 1 earthquake.

Therefore, we can conclude that a magnitude 8 earthquake is:

10^7 / 10^2 =

10^(7-2) =

10^5

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

answer4 to the second power is 16

and 4 to the third power is 64,