There are 70 balls of five different colors in a box. Suppose that if 60 balls are taken, then at least one ball of each color appears among the taken balls. What is the minimum number of balls that must be taken so that at least four different colors appear among the taken balls?

i dont know

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

my guess would be b and d, but i didn’t actually get out the pen and paper. lol

-1   1/6.   you dont subtract the denominators

step-by-step explanation: