Prove that they are equal

Step-by-step explanation:

(1-tanx)/(1+tanx) = (1-sin2x)/cos2x

Replace tanx with sinx/cosx:

(1-sinx/cosx)/(1+sinx/cosx)

Multiply numerator and denominator by cosx:

(cosx-sinx)/(cosx+sinx)

Multiply numerator and denominator by cosx-sinx:

(cos^2x-2sinxcosx+sin^2x)/(cos^2x-sin^2x)

For the numerator, since sin2x = 2sinxcosx, and sin^2x + cos^2x = 1, we have 1-sin2x

For the denominator, cos^2x - sin^2x = cos2x

So (1-tanx)/(1+tanx) = (1-sin2x)/cos2x

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

answer: '

the distance between points l and m

step-by-step explanation: