About two-thirds of companies in America test newly-hired employees for drugs and 3.8% of those prospective employees test positive (based on data from the American Management Association).
The Sigma Electronics Company tests 150 prospective employees.
If the 3.8% is assumed to be accurate, find the probability that 20 or more (out of 300) will test positive.
What is the chance that less than ten will test positive? Use the normal approximation to the binomial.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

1/8 3/16 3/4

step-by-step explanation:

you put them as all the same denominator and multiply