For ΔABC, ∠A = 8x - 10, ∠B = 10x - 40, and ∠C = 3x + 20. If ΔABC undergoes a dilation by a scale factor of 1 2 to create ΔA'B'C' with ∠A' = 6x + 10, ∠B' = 70 - x, and ∠C' = 10x 2 , which confirms that ΔABC∼ΔA'B'C by the AA criterion?

It does not confirm that ΔABC∼ΔA'B'C by the AA criterion as the measure of angle B is negative which is not possible.

Step-by-step explanation:

Since we have given that

In ΔABC,

∠A = 8x - 10, ∠B = 10x - 40, and ∠C = 3x + 20

In ΔA'B'C',

∠A' = 6x + 10, ∠B' = 70 - x, and ∠C' = 10x 2

Since ΔABC gets a dilation by a scale factor of

So, it becomes,

Now, put the value of

It does not confirm that ΔABC∼ΔA'B'C by the AA criterion as the measure of angle B is negative which is not possible.

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*

900 degrees

step-by-step explanation: