Omar's Coffee Shop makes a blend that is a mixture of coffee types A and B. In one bag of the blend, there are 4 kilograms of type A. Six bags of the blend are a total of 48 kilograms. How many kilograms of type B are there in one bag?

4kg type B coffee in each of the bags

Step-by-step explanation:

In this question, we are obviously dealing with coffees. Shouldn’t be too hard, right? Okay!

We are tasked with finding the amount in kilograms of type B coffee present in a bag of coffee.

We already know that in a bag , there are 4kg of type A coffee. Hence, in 6 bags, what we will be having would be 6 * 4kg = 24kg of type A coffee

The total kilograms of coffee in 6 bags of coffee is 48kg. Now we know we have 24kg of type A, the amount of type B coffee present is thus 48kg -24kg = 24kg

In one bag? This is equal to 24kg/6 = 4kg type B coffee in each bag

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet