PLEASE HELP. GOOGLE HAS FAILED ME.
Suppose f(x)=sin(pi cos(x))
On any interval where the inverse function y=f^-1(x) exists, the derivative of f^-1(x) with respect to x is:
A. -1/(cos(pi cos x)
B. -1/(pi sin(x) cos( pi cos(x)))
C. -1/(pi sin(y) cos(pi cos(y))
D. -1/(cos(pi cos(y))
E, -1/(sin(y) cos(pi cos(y))

b

Step-by-step explanation:

answer: options?

step-by-step explanation:

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: