Let the sample space be Upper S equals StartSet 1 comma 2 comma 3 comma 4 comma 5 comma 6 comma 7 comma 8 comma 9 comma 10 EndSet. Suppose the outcomes are equally likely. Compute the probability of the event Upper E equals StartSet 1 comma 4 comma 7 comma 9 EndSet.

Probability of event E = (4/10) = 0.40

Step-by-step explanation:

Note that n(E) is the number of outcomes in E

n(S) is the number of outcomes in S

And with each outcome having equal likelihood of occurring,

SetS = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}.

n(S) = 10

Event E = {1, 4, 7, 9}.

n(E) = 4

Probability of event E = n(E)/n(S)

Probability of event E = (4/10) = 0.40

Hope this Helps!!

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(a) the volume of the cone is 20/3 in3

hence, option a is correct.