A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second. y=-16x^2+115x+130 y=−16x 2 +115x+130

3.59 s

Step-by-step explanation:

Given

height of rocket is given by

Rocket will be at it maximum height when

therefore

At rocket will be at its maximum height

6.9

step-by-step explanation:

simple math really

6 1/2 times 0.6 = 3.9

but if you are just doing 6 and not 6 1/2 then the answer is 3.6

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1