In the school library, 28% of the books are non-fiction. If there are 1.224 fiction books in
the library, what is the total number of books

1700 books

Step-by-step explanation:

We are given;

We are required to determine the total number of books.

First we determine the percentage of non-fiction books

We need to know that;

% of fiction books + % of non-fiction books = 100%

Therefore;

% of non-fiction books = 100 % - 28 %

                                    = 72%

Second we determine the total number of books

We know that;

Total number of books = 100%

But;

72% = 1,224 books

Therefore;

Total number of books = (1,224 × 100%) ÷ 72%

                                      = 1700 books

Hence, the library has a total number of 1700 books

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

unless if u could do my questions, if not i wouldn't want to