To increase sales, a cell phone store began giving a free month of service on some cell plan purchases. Customers were unaware whether they would receive the free month until after purchase. The store manager claimed that one in eight customers received the free month. Nine customers each buy a cell phone plan. Let X = the number of customers that receive a free month of cell phone service. Part A: Is X a binomial random variable? Explain. (3 points) Part B: What is the mean and standard deviation of X? Provide an interpretation for each value in context. (4 points) Part C: Three of the nine customers receive a free month of service. Is the store's claim accurate? Compute P(X ≥ 3) and use the result to justify your answer. (3 points)

a) Yes

b) The mean is 9/8

The standard deviation, σ, is 0.99

c) Very unlikely as P(X≥3) is  0.09189 << μ =0.125 .

Step-by-step explanation:

Yes, A binomial random variable is the amount of success obtained from a given number of independent trials where the  there are only two possible outcomes and the probability of success or failure for each trial remains the same.

For a binomial random variable, we have

the sample size given as n = number of trials = 9

p = The probability of success on a trial = 1/8

The mean is given as

n×p = 9 × 1/8 = 9/8

The standard deviation, σ, is given by

= = 0.99

c) It is unlikely that three of the nine customers receive a free month of service as

The probability of P(X≥3)

= 1-P(X<3)

P(X<3) = P(X=0) + P(X=1) + P(X=2)

= ₉C₀×(1/8)⁰×(7/8)⁹ + ₉C₁×(1/8)¹×(7/8)⁸ + ₉C₂×(1/8)²×(7/8)⁷

= 0.3006 + 0.38656 +0.221  = 0.908

Therefore, P(X≥3) = 1 - 0.908 = 0.09189  much lower than the mean.

d

step-by-step explanation:

the solution is in the picture

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺