Help cause I haven’t been paying attention in class hehehe

1) g ≥ 17

2) g > -10

3) g > -1

Step-by-step explanation:

1) 7 (g-19) ≥ -14  divide both sides by 7

g - 19 ≥ -2          add 19 to both sides

∴ g ≥ 17

2)   3(7g+17) > -19 + 14g

21g + 51 > -19 + 14g

21g - 14g> -19 - 51

7g > -70

g > -10

6(-6g+6) > -2(19g-17)

-36g + 36 > -38g + 34

-36g + 38g > 34 - 36

2g > -2

g > -1

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

16 is the absolute value

step-by-step explanation: