The ages of six girls are as follows;17,8,12,15,15,13 .what would be the age of the seventh girl that would make the mean age of all the girls to be 13 years

11 yrs

Step-by-step explanation:

Mean = sum of ages/number of ages

Let the age of the seventh girl be A

Given the addition of the age of the seventh girl will make the mean of the ages be 13,

So,

13 = 17+8+12+15+15+13+A/7

Add up the ages

13 = 80 + A /7

Cross multiply

80 + A = 13 x 7

80 + A = 91

Subtract 80 from both sides to isolate A

80 - 80 + A = 91 - 80

A = 11

The age of the seventh girl is 11

step-by-step explanation: the answer is 27. first multiply .32 by 25 which equals 8. then add 8 to 25 which gives you 33. then you subtract that from 6 since she gave 6 to her brother.

,, add !

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)