You invested money in two funds. Last year, the first fund paid a dividend of 9% and the second a dividend of 3%, and you received a total of $879. This year, the first fund paid a 10% dividend and the second only 1%, and you received a total of $839. How much money did you invest in each fund?

$7800 was invested at 9%

$5900 was invested at 3%

Step-by-step explanation:

Let x represent the amount invested in the fund that paid a dividend of 9%.

Let y represent the amount invested in the fund that paid a dividend of 3%.

Last year, the first fund paid a dividend of 9% and the second a dividend of 3%, and you received a total of $879. This means that

0.09x + 0.03y = 879- - - - - - - - - 1

This year, the first fund paid a 10% dividend and the second only 1%, and you received a total of $839. It means that

0.1x + 0.01y = 839 - - - - - - - - - -2

Multiplying equation 1 by 0.1 and equation 2 by 0.09, it becomes

0.009x + 0.003y = 87.9

0.009x + 0.0009y = 75.51

Subtracting, it becomes

0.0021y = 12.39

y = 12.39/0.0021

y = 5900

Substituting y = 5900 into equation 1, it becomes

0.09x + 0.03 × 5900 = 879

0.09x + 177 = 879

0.09x = 879 - 177

0.09x = 702

x = 702/0.09

x = 7800

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.