The distribution of the number of viewers for the American Idol television show follows a normal distribution with a mean of 26 million with a standard deviation of 8 million. What is the probability next week's show will: Have between 30 and 37 million viewers

Probability that next week's show will have between 30 and 37 million viewers is 0.2248.

Step-by-step explanation:

We are given that the distribution of the number of viewers for the American Idol television show follows a normal distribution with a mean of 26 million with a standard deviation of 8 million.

Let X = number of viewers for the American Idol television show

So, X ~ N()

Now, the z score probability distribution is given by;

          Z = ~ N(0,1)

where, = population mean = 26 million

            = standard deviation = 8 million

So, probability that next week's show will have between 30 and 37 million viewers is given by = P(30 < X < 37) = P(X < 37) - P(X 30)

    P(X < 37) = P( < ) = P(Z < 1.38) = 0.91621

    P(X 30) = P( ) = P(Z 0.50) = 0.69146

Therefore, P(30 < X < 37) = 0.91621 - 0.69146 = 0.2248

Hence, probability that next week's show will have between 30 and 37 million viewers is 0.2248.

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