As a student project Natalie would like to see whether there is statistical evidence Earth is warmer today versus 30 years ago. She randomly samples 100 locations around the world and collects the annual average high for each location for the years 1985 and 2015. She proceeds to compare the differences among the time periods with respect to location. What procedure should be used to test whether the average difference in temperature between the locations is greater than zero

Natalie would use a "test of difference between two means".

Step-by-step explanation:

First step: State the hypotheses of the test as follows;

Where are the Population means of years 1985 and 2015 respectively.

Second step: Determine the level of significance to be used for the testing. A 5% level of significance or 10% level of significance could be used.

Third step: Calculate the sample means and Variances for the two populations as follows;

where are the annual average high warmth for the years 1985 and 2015 respectively.

where are the respective sample variances for 1985 and 2015

and

Step three: The test statistic is computed as follows;

Step four: The Critical point for acceptance is calculated using the normal table and chosen level of significance. It is represented as

Step five: The decision rule is specified as follows:

Reject if , otherwise do not reject.

Step six: Conclusion is made based on the outcome of the test.

Note: used here represents "greater than"

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15