F(1)=1 and f(n)=f(n-1)^2+3
f(n)=f(n−1) 2 +3

then find the value of
f(4)

f(4) = 364

Step-by-step explanation:

f(1)=1

f(n)=f(n-1)^2+3

f(2) = f(1)^2 +3 = 1^2 +3 = 4

f(3) = f(2)^2 +3 = 4^2 +3 = 16+3 = 19

f(4) = f(3)^2 +3 = 19^2 +3 = 361+3 = 364

f(4) = 364

Step-by-step explanation:

f(n)=f(n-1)² +3

Since f(1) = 1

f(2) = [f(1)]² + 3

= 1² + 3

= 4

f(3) = [f(2)]² + 3

= 4² + 3

= 19

f(4) = [f(3)]² + 3

= 19² + 3

= 364