Suppose a bowler claims that her bowling score is not equal to 150 points, on average. Several of her teammates do not believe her, so the bowler decides to do a hypothesis test, at a 5% significance level, to persuade them. She bowls 22 games. The mean score of the sample games is 157 points. The bowler knows from experience that the standard deviation for her bowling score is 18 points.
H0: μ = 150; Ha: μ = /150
α = 0.05 (significance level)
(a) What is the test statistic (z-score) of this one-mean hypothesis test?

The test statistic (z-score) of this one-mean hypothesis test is z=1.823.

Step-by-step explanation:

The null and alternative hypothesis are:

The significance level is 0.05.

The sample size is n=22.

The sample mean is M=157.

The standard deviation is 18.

The z-score can be calculated as:

The test statistic (z-score) of this one-mean hypothesis test is z=1.823.

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answer: d.) the total number of protons and neutrons is 15

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your friendly neighborhood human spider! .

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.