Find the least number that has each pair of numbers as factors 1.a) 10 and 15 b.) 8 and 28 2.a) find the first 3 common multiples of each pair of numbers in question 1. b.

step-by-step explanation:

what are the statements? and what do you mean by "216 2 1 6"?

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice

move it to the other side

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116