A poll is to be conducted to find out how many books, on average, Canadians read. You are the person who is to select a random sample and to ask the people of the sample about the number of books they read in the previous year. How many people are needed for your sample to estimate the number of books within 3 books with 90% confidence? Assume that it is known that the standard deviation for number of books read by Canadians is 14.1 books

So the answer for this case would be n=60 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

represent the sample mean for the sample  

population mean (variable of interest)

represent the sample standard deviation

n represent the sample size  

Solution to the problem

The margin of error is given by this formula:

   (a)

And on this case we have that ME =3 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

  (b)

The critical value for 90% of confidence interval now can be founded using the normal distribution. And in excel we can use this formula to find it:"=-NORM.INV(0.05;0;1)", and we got , replacing into formula (b) we got:

So the answer for this case would be n=60 rounded up to the nearest integer

step-by-step explanation:

the answer is 150.6

step-by-step explanation:

you multiply .02 by 30 and get .6.

and then you multiply 5.00 by 30 and get 150.

hope this !