Q10. A, B, C, D is a quadrilateral with AB = 8.5cm; AC = 10.4cm and
BC = 7cm.
Given that D is equidistant from A and C; and angle ADC = 60°
(i) construct, using ruler and pair of compasses only and leaving all constructional
lines clearly visible, the quadrilateral A, B, C, D;
[4 marks]
(ii) locate a point M, the locus of points equidistant from AB, AD and BC.
[2 marks]
(iii) construct a circle to touch the sides AD, AB and BC [2marks]
(iv) shade the region inside the circle and less than BM. [2 marks]
(b) Measure the radius of the circle.
[2marks]

i believe it is 0.1m because the measurement of 30.4m limits how precise you can be

you can only be as precise as the least precise measurement

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.