Rhombus $ABCD$ has perimeter $148$, and one of its diagonals has length $24$. What is the area of $ABCD$?

70 units (correct me if I'm wrong...)

Step-by-step explanation:

148/4 = n

n = 37

37 = 1/2 x 24 = 12 (12 x 2 = 24...)

x^2 = 37^2 - 12^2 = 1225

sub in 35 for the x's

which makes x=35

this half of the other so it equals =70 for the next

(MARK BRAINLIEST IF CORRECT...)

the barter