Here are the first four tearms of a sequence 1, 11, 22, 37, find and express in terms of n the nth term of this sequence

2n² + n + 1

Explanation:

The sequence is 4, 11, 22, 37

Difference between:  7, 11, 15

The first differences are 7, 11, 15, and the second differences are 4.

Since half of 4 is 2, then the first term will be 2n^2.

Subtracting 2n² from the sequence gives 2, 3, 4, 5 which has nth term n + 1.

Therefore the final answer is 2n² + n + 1

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x