Shreya has five more than twice the number of chocolates as her sister Priya. If Priya has ‘y’ chocolates, write an algebraic expression for the number of chocolates Shreya has.
If the total number of chocolates they have is 95, how many chocolates do each of them have?

Priya= y

Shreya= 2y+5

Shreya+Priya=95

2y+5=95

3y+5=95

3y=90                             By subtracting 5 from both sides

y=30                                By dividing by 3 on both sides

Priya=y= 30 chocolates

Shreya= 2y+5= 2(30)+5=60+5=65 chocolates

I hope this helps :)

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

whats the rest of it?