Quadrilateral ABCD is inscribed in a circle with angle measures m
*PLEASE ANSWER IMMEDIATELY*

B and D

Step-by-step explanation:

First method :

All angles of a quadrilateral sums to 360 degrees

A + B + C + D = 360

=> 5x^2 + 36x - 336 = 0

=> x = 6 or x = - 56/5 [It gives negative value of angles]

So, A = 58, B =  109, C = 122, D = 71

Second method :

Sum of opposite angles of a quadrilateral inscribed in a circle is 180 degrees

A + C = 180

=> x = 6

So, A = 58, B =  109, C = 122, D = 71

[If there's any mistake, please inform me]

i would need to see the dot plot : )

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.