1. If the co-interior angles formed by a transversal and the two line segments are supplementary the two segments are parallel. Determine whether DE is parallel to BC

2. What can you conclude about the heights of (triangle) ADE and (triangle) ABC? How is the height of triangle ADE related to the the height of quadrilateral BCED? Explain.

3. Does this apply for all triangles? Explain your reasoning.

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

his first public project he is asked to create a small scale drawing. the garden is a right triangle with base 25m and height 30m. are you trying to solve for the last side/hypotenuse? the irrational form of the answer would be 5\sqrt{61}

486in is correct

step-by-step explanation: