A gas station stores its gasoline in a tank under the ground. The tank is a cylinder lying horizontally on its side. (In other words, the tank is not standing vertically on one of its flat ends.) If the radius of the cylinder is 2 meters, its length is 6 meters, and its top is 4 meters under the ground, find the total amount of work needed to pump the gasoline out of the tank. (The density of gasoline is 673 kilograms per cubic meter; use g

The question given is incomplete, here is the complete one gotten from google:

A gas station stores its gasoline in a tank under the ground. The tank is a cylinder lying horizontally on its side. (In other words, the tank is not standing vertically on one of its flat ends.) If the radius of the cylinder is 2 meters, its length is 6 meters, and its top is 4 meters under the ground, find the total amount of work needed to pump the gasoline out of the tank. (The density of gasoline is 673 kilograms per cubic meter; use g=9.8m/s^2

Work = 2,238,031 Joules

Step-by-step explanation:

Assuming the tank is initially full, and work is needed to be done to make it empty, and get the fuel to the ground level.

The tank center line is the center of gravity of the fuel, and its distance below ground level is 4+ 0.5 m m= 4.5 m.

Fuel mass = π * (2)²*6*673 = 3.142*6*673 =  50,749 Kg

Work = weight*height

= mass*acceleration due to gravity,g*height

=50,749*9.8*4.5 = 2,238,030.9

Work = 2,238,031 Joules

pooopoopopoopop

step-by-step explanati∵∵∴∴on:

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10