Mr. Clark has a tank that holds 55,000 milliliters of gas. He poured some gas into three containers equally. There were 19,864 milliliter of gas left in the tank. How much gas was poured out of the tank

35,136 ml

Step-by-step explanation:

The tank holds 55,000ml. Mr. Clark poured some gas into 3 container, and at the end there the tank had 19,864. To find how much gas was poured out of the tank it is the same as asking how much gas he poured in the 3 containers, all together. We have to find the difference, subtraction:

55,000 - 19,864 = 35,136ml were poured in the 3 containers or amount of gas poured out of the tank.

cheater

step-by-step explanation:

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .