7. What is the least of four consecutive integers whose sum is 58? *
1 point
A. 1
B. 2
C.12
D. 13

13

Step-by-step explanation:

represent the first integer as x

Since they are consecutive, you can represent the others as x+1, x+2, and x+3.

Write the equation

x + (x +1) + (x+2) + (x+3) = 58

Combine like terms

4x + 6 = 58

Solve for x

4x= 52

x=13

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}

x= 3^y

step-by-step explanation: