(x+3)(x4)
X=-3 X=-
2x(x+3)+(x+3)=0
2x+1 X3
Applications of quadratic equations:
1. Suppose that one leg of a right triangle is 1 more than the other leg; and the hypotenuse is 1 less than 2 timest
shorter leg. Find the lengths of all the sides.
2.A square had 9 cm added to its length and 3 cm added to its width. Its new area is 280 square cms. Find the le
of each side of the original field.
(x+4) (x+3)=280 x?+23x-x-253-0
X249x+3x+27 XOX423) – 11(x+23)=0
V2 283-0 cm