Find an equation of the line that passes through the points (-1/2,3/4) and (3/4,-1/2)

A. y=x+4
B. Y=-x+1/4
C. Y=5x-4/7
D. Y=-5x-7/4

B. y = -x + 1/4

Step-by-step explanation:

The equation of a line is

y = mx + c

step 1: find the slope

m = y2 - y1 / x2 - x1

Given two points

( -1/2 , 3/4) ( 3/4, -1/2)

x1 = -1/2

y1 = 3/4

x2 = 3/4

y2 = -1/2

Insert the values into the equation

m = ( -1/2 - 3/4) / ( 3/4 - (-1/2)

m = ( -1/2 - 3/4) / ( 3/4 + 1/2)

m = -5/4 / 5/4

m = -5/4 * 4/5

m = -5 * 4 / 4 * 5

= -20/20

= -1

Step 2: substitute m into the equation

y = mx + c

y = -1x + c

y = -x + c

Step 3: sub any of the two points given into the equation

Let's pick ( 3/4 , -1/2)

x = 3/4

y = -1/2

y = -x + c

-1/2 = -3/4 + c.

c = -1/2 + 3/4

LCM = 4

c = -2 + 3 / 4

= 1/4

y = -x + 1/4

The equation of the line is

y = -x + 1/4

ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga

step-by-step explanation:

its the fourth option