Two of the desserts are sugar/free. Three of the drinks are sugar-free. A meal deal combination is selected at random. Work out the probability that both the desserts and the drink are sugar free. Give your answer as a fraction

1/4

Step-by-step explanation:

So the first answer to this question (a) is 120 as you do 5x4x6, so for the next question you need to do the same method, but only including the sugar free options. So we still have all the sandwiches, so its still 5, then x 2 because that's how many sugar free desserts there are, and x 3 because that's how many sugar free drinks there are. So 5x2x3=30, and 30/120 (as it is a fraction) can be simplified to 1/4

step-by-step explanation:

this is not a question