What is an equation of a line which passes through
(6,9) and is perpendicular to the line whose
equation is 4x - y = 15?

y= -1/4x + 10.5

Step-by-step explanation:

First you need to change the equation to write it in slope intercept form. Subtract 4x from both sides and then divide both sides by a negative sign.

4x - y = 15

-4x        -4x

-y = -4x +15

y = 4x+15

To find the perpendicular slope of the line you must find the inverse of the original slope. The original slope is 4x so the inverse of 4x would be -1/4x. Now that you have your slope you must find the y intercept. You can do this by inputting the x and y values into the equation of a line which is y= mx +b

9 = -1/4(6) + b

9 = -1.5 + b

+1.5         +1.5

10.5 = b



c: lkllmn.

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