What is the axis of symmetry of the parabola y=5x2+6

x=0

Step-by-step explanation:

The quadratic equation is written in the form

y = ax^2 +bx+c

The axis of symmetry is h

h= -b/2a

Our equation is

y = 5x^2 +0x +6

a =5  b=0  and c=6

h = -0/2(5)  = 0

The axis of symmetry is x=0

on your paper it doesn't say the answer but the the answer is altitude

step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !