A weight is suspended from a spring and allowed to hang at its rest posistion. it is then pulled down 2 in.,released, and allowed to oscillate up and down. its location (in inches) relative to its rest posistion is given by the function f(t)=2sin(2.5t-pie/2), where t is the time in seconds. how much time will it take for the weight to move through one complete cycle of motion?

1 )2.5 sec

2)3.1sec

3)3.8sec

4)5.0sec

The weight will complete a full cycle in 2.5 seconds.

Step-by-step explanation:

The weight is pulled down 2 inches, released, and allowed to oscillate up and down.

Now, its location (in inches) relative to its rest position is given by the function , where t is the time in seconds.

Now, the initial position of the weight was at f(0) = - 2 inches and again after t seconds, it will reach -2 inches distance to complete a cycle.

Then,

⇒

⇒

⇒ 2.5t = 2π

⇒ t = 2.5 seconds (Approximate)

Therefore, the weight will complete a full cycle in 2.5 seconds. (Answer)

13875138answer:

step-by-step explanation:

use a calculator!

required rate of return = 0.166 = 16.6%

step-by-step explanation:

under the capital asset pricing model (capm), the required or expected rate of return for a particular security or asset is given using the formula:

required rate of return = risk-free rate + beta*(market risk premium)

we are given that;

risk-free rate = 4% = 0.04

beta = 1.4

market risk premium = 9% = 0.09

we simply plug these values into the above formula;

required rate of return = 0.04 + 1.4*(0.09)

required rate of return = 0.04 + 0.126

required rate of return = 0.166 = 16.6%