Makoto and his friends rolled two fair number cubes 500 times and recorded the sum of the numbers shown on the cubes each time. On 42 of the trials the sum was 10

1/12

Step-by-step explanation:

I think your question missed key information, allow me to add in as the following:

Makoto and his friends rolled 2 fair number cubes 500 times & recorded the sum of the numbers shown on the cubes each time. On 42 trials the sum was 10. which of these is most likely the probability that the sum of the numbers shown on the cubes is 10 when 2 fair number cubes are rolled?

a.) 1/6

b.) 1/12

c.) 1/25

d.) 1/50

Here is my

Given that: On 42 trials the sum was 10

It means there are 3 possible outcomes which are: 5&5, 4&6 and 6&4

As we know, each cube has 6 side, we roll 2 cubes at the same time so the possible outcome for this situation is: 6*6 = 30

Therefore, the probability that the sum of the numbers shown on the cubes is 10 when 2 fair number cubes are rolled is:

Choose B

Hope it will find you well

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step-by-step explanation: