What is the result of subtracting the second equation from the first? \begin{aligned} x-3y &= 6 -8x-y &= 6 \end{aligned} x−3y −8x−y =6 =6

Therefore the required result is 9x-2y =0.

Step-by-step explanation:

Given equation are

x-3y =6(1)

-8x-y=6 (2)

Subtracting equation (2) from (1)

 x  -  3y = 6

-8x  -  y=  6

+     +      -                 [ The sign of equation (2)  will be change in case of          

              subtraction and in case of plus the signs remains same ]

(x+8x)-3y+y=6-6   [ adding the like terms]

⇒9x-2y =0

Therefore the required result is 9x-2y =0.

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this

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step-by-step explanation: