Consider a binomial experiment with n=11 and p=0.3. a. Compute (to 4 decimals). b. Compute (to 4 decimals). c. Compute (to 4 decimals). d. Compute (to 4 decimals). e. Compute (to 1 decimal). f. Compute and . (to 2 decimals) (to 2 decimals)

a. Compute f(0) (to 4 decimals).

b. Compute f(7) (to 4 decimals).

c. Compute P(x≤1) (to 4 decimals).

d. Compute P(x≥3) (to 4 decimals).

e. Compute E(x) (to 1 decimal).

f. Compute V(x) and σ. (to 2 decimals)

Step-by-step explanation:

The question is incomplete:

a. Compute f(0) (to 4 decimals).

b. Compute f(7) (to 4 decimals).

c. Compute P(x≤1) (to 4 decimals).

d. Compute P(x≥3) (to 4 decimals).

e. Compute E(x) (to 1 decimal).

f. Compute V(x) and σ. (to 2 decimals)

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

b

step-by-step explanation:

the word superfluous means unnecessary