Students who party before an exam are twice as likely to fail as those who don't party (and presumably study). If 20% of the students partied before the exam, what fraction of the students who failed went partying? unanswered

The fraction of the students who failed to went partying =

Step-by-step explanation:

Let total number of students = 100

No. of students partied are twice the no. of students who not partied.

⇒ No. of students partied = 2 × the no. of students who are not partied

No. of students partied before the exam = 20 % of total students

⇒ No. of students partied before the exam = × 100

⇒ No. of students partied before the exam =  20

No. of students who not partied before the exam =

Thus the fraction of the students who failed to went partying =

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.