In triangle ABC, angle a and b are complementary, where the cos A= 0.5. What is the angle measure of B in degrees?

Angle B measures 30 degrees.

Step-by-step explanation:

Step 1:

If two angles are complementary, the sum of the two angles will equal 90°.

So if angles A and B are complementary, the sum of the angles A and B will equal 90°.

It is given that cos A = 0.5, we can determine the value of A by taking the cos inverse of the value 0.5.

Step 2:

If cos A = 0.5, A = So angle A is 60°.

As A and B are complementary, angle A + angle B = 90°.

So 60° + angle B = 90°, angle B = 90° - 60° = 30°.

So angle B measures 30° while angle A measures 60°.

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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