A spherical scoop of vanilla ice cream with radius of 2 inches is dropped onto the surface of a dish of hot chocolate sauce. As it melts, the ice cream spreads out uniformly forming a cylindrical region 8 inches in radius. Assuming the density of the ice cream remains constant, how many inches deep is the melted ice cream

1/6in

Step-by-step explanation:

In order to find the height of the melted ice-cream, first we need to find volue of a sphere then a cylinder and equate them.

As we know, the volume of a sphere is defined as:

 V = (4/3)π·r³

therefore, scoop has:

 V = (4/3)π·(2 in)³ => 32π/3 in³

Next is to find the volume of a cylinder

V = π·r²·h=> π·(8 in)²·h

Since the cylinder has the same volume as the sphere, we have

 32π/3 in³ = π·(8 in)²·h   (simplifying the equation)

 We have, h = (32π in³)/(3x64π in²) = 1/6 in

h=1/6in

it's d.

step-by-step explanation:

because: -1(4x + 1y) +2 (1x-3y) distribute each number into the parenthesis.

then you would get: -4x - 1y + 2x -6y combine like terms

and get: 2x -7y

hope my answer has you if not then i'm sorry.