Given
LM
←
→
−
tangent to ⊙C at point L, which is an expression to represent
m
JK


A.
360° – (a + b)°

B.
360° – 2(a + b)°

C.
360° – (2a + b)°

D.
360° + (2a + b)

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

6 adults and 9 children went.

a + c = 15

12a + 9c = 153

12(6) + 9(9) = 153

72 + 81 = 153

the answer on ed. is:

c. "the graph of f(x) has exactly two x-intercepts."

hope i could someone! : )

use photo math thats what i use u can scan the problem and it tells u the answer